By Shirley O. Hockett, David Bock

ISBN-10: 0764143247

ISBN-13: 9780764143243

Either Calculus AB and Calculus BC are lined during this entire AP try out training handbook. potential attempt takers will locate 4 perform assessments in Calculus AB and 4 extra in Calculus BC, with all questions responded and ideas defined. The guide additionally offers an in depth 10-chapter evaluate masking subject matters for either assessments. The authors additionally provide an outline of the AP Calculus tests, consisting of recommendation to scholars on making top use in their graphing calculators.

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**Additional info for AP Calculus**

**Example text**

M. M. M. M. Midnight 5 2 3 8 10 16 5 People per minute (A) 5280 (B) 10,080 (C) 10,440 (D) 10,560 (E) 15,840 36. The acceleration of a particle moving along a straight line is given by a = 6t. If, when t = 0, its velocity, v, is 1 and its position, s, is 3, then at any time t (A) s = t3 ϩ 3 (D) s = (B) s = t3 ϩ 3t ϩ 1 t3 +t+3 3 (E) s = (C) s = t3 ϩ t ϩ 3 t3 t2 + +3 3 2 37. If y = f(x2) and f ′( x ) = 5 x − 1 then dy is equal to dx (A) 2 x 5 x 2 − 1 (B) 5x − 1 2x (D) 5x − 1 (C) 2 x 5 x − 1 (E) none of these 38.

Which of the following statements is (are) true? 1 + et I. F′(0) = 5 II. F(2) < F(6) III. F is concave upward. (A) I only (B) II only (C) III only (D) I and II only (E) I and III only 43 7_3679_APCalc_02DiagnosticBC 44 10/3/08 4:19 PM Page 44 AP Calculus 15. 96, which is closest to f ′(1)? 5 (E) 24 16. If f is differentiable, we can use the line tangent to f at x = a to approximate values of f near x = a. Suppose this method always underestimates the correct values. If so, then at x = a, the graph of f must be (A) positive (B) increasing (C) decreasing (D) concave upward (E) concave downward 7.

A 26-foot ladder leans against a building so that its foot moves away from the building at the rate of 3 feet per second. When the foot of the ladder is 10 feet from the building, the top is moving down at the rate of r feet per second, where r is (A) 46 3 42. If F ( x ) = ∫ 2x 1 (A) (C) 5 4 (B) 3 4 (D) 5 2 (E) 4 5 1 dt , then F ′(x) = 1 − t3 1 1 − x3 (B) 1 1 − 2x3 2 1 − 2x3 (C) (D) 1 1 − 8x3 (E) 2 1 − 8x3 a(ft/sec2) 2 t (sec) 1 2 3 4 5 –2 43. The graph above shows an object’s acceleration (in ft/sec2).

### AP Calculus by Shirley O. Hockett, David Bock

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